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3x^2=(1/9)^x-4
We move all terms to the left:
3x^2-((1/9)^x-4)=0
Domain of the equation: 9)^x-4)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3x^2-((+1/9)^x-4)=0
We multiply all the terms by the denominator
3x^2*9)^x-4)-((+1=0
Wy multiply elements
27x^3+1=0
We do not support expression: x^3
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